1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan [553]
3 years ago
6

Somebody, please help

Mathematics
1 answer:
SashulF [63]3 years ago
5 0
F(x) can be written as:
f(x) = Asin(2x); where A is the amplitude and the period of the function is half that of a normal sin function.
f(π/4) = 4
4 = Asin(2(π/4))
4 = Asin(π/2)
A = 4
Amplitude of g(x) = 1/2 * amplitude of f(x)
A for g(x) = 2
g(x) = 2sin(x)
You might be interested in
-3x - y = 0 and -8x +5y=7
andrezito [222]

Answer:

-23x = 7

Step-by-step explanation:

-3x - y =0

×5. ×5 ×5

-15x -5y = 0

-8x +5y = 7

-15x -5y -0

-23x = 7

8 0
3 years ago
Avg these<br> 190258.50<br> 152698.00<br> 122753.00<br> 220523.00<br> 231951.00
Andre45 [30]
To get an average, you must do the following steps.

step 1:add all the numbers together.
190258.50+152698.00+122753.00+220523.00+231951.00= 918183.5Step 2: divide the ANSWER you get by the amount of numbers there are:
(in this case, it will be 5, because you added 5 numbers together)
918183.5/5


your answer is: 183636.7
that is your average

hope this helps :D
6 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
Add the polynomials. (9x2 - 6x +6) + (7x3 - 9x)
Alchen [17]

Answer:

-15x+45 should be your answer

Step-by-step explanation:

4 0
3 years ago
What is the domain and range of this map?
uranmaximum [27]

The domain and the range is [-6 to +inf)


7 0
3 years ago
Other questions:
  • Find the most common multiples of 2 an 5
    9·1 answer
  • A circle has an area of 75 square centimeters. Which answer is closest to the measure of its radius?
    6·2 answers
  • Quotient of 120 and 10
    7·2 answers
  • Determine each unknown addend ___ + 41=-18
    11·1 answer
  • Solve for x. 2x−45=x+4 Enter your answer in the box. x =
    15·1 answer
  • Nevermind sorry!!!!!!!!!!!!!!!!!!!
    14·2 answers
  • Machine A pops 12.75 ounces of popcorn in 3 minutes. Machine B pops 18 ounces of popcorn in 4 minutes. If each machine pops popc
    7·2 answers
  • A right cylinder has a radius of 2 units and a height of 5
    6·2 answers
  • The formula shows that c, the total cost of buying pizzas at Al's restaurant depends on p, the number of pizzas ordered.
    10·1 answer
  • Can someone help me on all three of these
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!