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3 years ago

7

EXPERTS/ACE OR PEOPLE THAT KNOW IT QUICK PLZ. !!

1 answer:

dezoksy [38]3 years ago

6 0

Assuming that there is only 1 bag, there is a set value (we can call that b) for that cost. In addition, there is a set value for what the bag weighs. We can call that m. Therefore, for x pounds, we multiply the amount per pound by the amount of pounds (x) to get m*x+b=cost (y). In a line mx+b=y, m is the rate of change. m can be found by
$\frac{y1-y2}{x1-x2}$

Using that, with the cost being the y values and the amount of pounds being the x values, we have (20, 25) at one point and (50, 40) at another. For our equation, we have
$\frac{40-25}{50-20} = \frac{15}{30}$

Dividing both the numerator and denominator by 15 (we know they are both factors of 15 with a little guess and check), we have 1/2 or 0.5 as our answer

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Step-by-step explanation:

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What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.

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Answer:

C) $\theta\approx\{0.3218,1.249,3.463,4.3908\}$

Step-by-step explanation:

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2 years ago

s2008m [1.1K]

A= 1/4E
B= 4E
C= E-4
D= E+4
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4 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

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3 years ago

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rusak2 [61]

The correct answer is Z=-13

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2 years ago

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