Data Given:
Volume = V = 44.8 L
Standard Pressure = P = 1 atm
Standard Temperature = T = 273 K
According to Ideal Gas Equation,
P V = n R T
Solving for n,
n = P V / R T
Putting values,
n = (1 atm × 44.8 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)
n = 1.99 mol
Now, calculating for mass,
n = Mass / M.mass
Or,
Mass = n × M.mass
Mass = 1.99 mol × 28 g.mol⁻¹
Mass = 55.72 grams
Answer:
A
Explanation:
Neutralization reaction is
base + acid ---> salt + water.
Answer:
V= 13 m/s
Explanation:
We're asked to find the magnitude of the object's velocity after a force is applied for
3
s
parallel to its motion.
We'll call the direction it's moving the positive
x
-axis, and the direction of the applied force the positive
y
-axis.
The components of the initial velocity are
v
0
x
=
5
m/s
v
0
y
=
0
(It's moving at
5
meters per second in the straight line we called the
x
-axis.)
We know the object's mass is
3
kg
, and the force applied is
12
N
in the positive
y
-direction. The magnitude of the constant acceleration is thus
a
y
=
∑
F
y
m
=
12
l
N
3
l
kg
=
4
m/s
2
Since this acceleration is directed upward, and the initial
y
-velocity is
0
, we can use the kinematics equation
v
y
=
v
0
y
+
a
y
t
to find the
y
-velocity after
3
seconds.
Plugging in known values, we have
v
y
=
0
+
(
4
l
m/s
2
)
(
3
l
s
)
=
12
m/s
No acceleration was applied in the
x
-direction, so it's
x
-velocity remains
5
m/s
. The magnitude of the velocity is thus
v
=
√
(
v
x
)
2
+
(
v
y
)
2
=
√
(
5
l
m/s
)
2
+
(
12
l
m/s
)
2
=
13
m/s
Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.
The answer should be "Satellite." The satellite is placed in the exosphere which allows it to take pictures of the clouds from above, which is also how NASA gets most of it's pictures of the planet.
Hope this helps!
