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3 years ago

When the moon is between the Sun and the Earth, it is completely in the shadows. What is the lunar phase called?

Chemistry

2 answers:

Maslowich3 years ago

7 0

Lunar eclipse because i really need points fam

Tju [1.3M]3 years ago

4 0

When the moon is completely covered by a shadow it is known as a new moon.

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Conversion factors are useful in solving problems in which a given measurement must be expressed in

spin [16.1K]

Conversion factors are useful in solving problems in which a given measurement must be expressed in some other units of measure.

Conversion factors are helpful in solving issues where one unit of measurement needs to be expressed in another. In general, a measurement's numerical value changes when it is multiplied by a conversion factor, while the quantity being measured's real size stays the same.
A conversion factor is a number that is used to multiply or divide one set of units into another. If a conversion is required, it must be done using the correct conversion factor to get an identical value. For instance, 12 inches equals one foot when converting between inches and feet.

To learn more about Conversion factors please visit -brainly.com/question/23510660
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4 0

2 years ago

Each solute in the table is mixed in a volume of 500 mL of water. Organize the solutions from least conductive to most conductiv

Murljashka [212]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu

chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\pi r^3$ ..[1]

Diameter of the nucleus ,d' = $9.00\times 10^{-5}\AA$

Radius of the nucleus ,r' = 0.5 d'= $0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA$

Volume of nucleus = V'

$V=\frac{4}{3}\pi r'^3$ ..[2]

Dividing [2] by [1]

$\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}$

$=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}$

$\frac{V'}{V}=4.6656\times 10^{-14}$

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

Diameter of the proton ,d = $1.72\times 10^{-15} m = 1.72\times 10^{-13} cm$

1 m = 100 cm

Radius of the proton,r = 0.5 d= $0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm$

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3$

Mass of proton, m = 1.0073 amu = $1.0073\times 1.66054\times 10^{-24} g$

$1 amu = 1.66054\times 10^{-24} g$

Density of the proton : d

$d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3$

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

5 0

4 years ago

What is the ratio of lactic acid (Ka = 1.37x^10-4) to lactate in a solution with pH =4.29

hram777 [196]

Henderson–Hasselbalch equation is given as,

pH = pKa + log [A⁻] / [HA] -------- (1)

Solution:

Convert Ka into pKa,

pKa = -log Ka

pKa = -log 1.37 × 10⁻⁴

pKa = 3.863

Putting value of pKa and pH in eq.1,

4.29 = 3.863 + log [lactate] / [lactic acid]

Or,

log [lactate] / [lactic acid] = 4.29 - 3.863

log [lactate] / [lactic acid] = 0.427

Taking Anti log,

[lactate] / [lactic acid] = 2.673

Result:

2.673 M lactate salt when mixed with 1 M Lactic acid produces a buffer of pH = 4.29.

6 0

4 years ago

Does anyone know the answer to this (science)

IRISSAK [1]

I think the answer is c ... could be all but I pretty sure it’s c

8 0

3 years ago

Read 2 more answers