Help asap!!!!!!!! How much net force is required to accelerate a 50.00 kg mass at 4.00 m/s??
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The sign's glass absorbed 25466.7 J
<h3>Further explanation</h3>Given
The temperature of glass : 23.5 °C to 65.5 °C
mass = 905 g
the specific heat capacity = 0.67 J/g °C
Required
Heat absorbed
Solution
Heat absorbed by sign's glass can be formulated :
ΔT=65.5 - 23.5 = 42