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4 years ago

When water reaches its boiling point and turns into water vapor what happens to its molecular structure

1 answer:

8 0

When water reaches its boiling point and turns into water vapor, the molecular structure of water remains the same. It is only the state of the substance that is changed in this process. I hope this helps you

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Determine the mass in grams of Avogadro's number of C12H22O11

Allushta [10]

Answer:

2.059524x10^26 if im not wrong

Explanation:

avogadro's number is 6.022x10^23

5 0

3 years ago

What is the momentum of a 1,700 kg car travelling in a straight line at 13 m/s?

Anna71 [15]

Answer:

Explanation:

We know that momentum is the product of mass and velocity so here

mass (m) = 1700 kg

velocity (v) = 13 m/s

So now

momentum = m * v

= 1700 * 13

= 22100 kg m/s

hope it helps :)

4 0

3 years ago

what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?

Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0

3 years ago

A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.

GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂ + I₂ ⇄ 2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

H₂ + I₂ ⇄ 2HI

In: 0.001 0.002 -

R: x x 2x

Eq: 0.001-x 0.002-x 0.00187

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is = (HI)² / (H₂) . (I₂)

0.00187 ² / 6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0

3 years ago

He atomic number of carbon is 6. carbon-14 is heavier than carbon-12 because the atomic nucleus of carbon-14 contains _____ neut

Marta_Voda [28]

14-6=8
8 neutrons is the answer

5 0

3 years ago