Answer:
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
Explanation:
As we know
Amount of heat gained
Q = mc (T2-T1)
Here,
mass of water in cup 2 (m) = 79.10 grams
Temperature of water in cup 2 = 16.8 degree Celsius
Specific heat of water (c) = 4.186 J/(g °C)
Final Temperature of water in cup 2 = 23.2 degree Celsius
Substituting the given values, we get -
Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
Answer:
B and C
Explanation:
Selective breeding is a procedure that involves the purposeful breeding of selected parents in order to give rise to offsprings with desired traits. Selective breeding procedure has its own advantages, which includes the ability to produce more animal products such as milk, meat etc, however, it has disadvantages.
The disadvantages include that:
- Selectively bred animals are more likely to have some health problem
- Some desirable traits become more common in a population.
Answer:
0.473 moles
Explanation:
(2.85x10e23)/(6.02x10e23) = 0.47342
Answer:
<h2>36.09 L</h2>
Explanation:
The initial volume can be found by using the formula for Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume.
Since we're finding the initial volume
We have
We have the final answer as
<h3>36.09 L</h3>
Hope this helps you
