1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
10

Joe is the best baseball player in the world. He can throw a baseball faster than anyone. If the mass of the baseball was increa

sed by 50%, but he applied the same force as he did to a lighter baseball, which of these would best describe Joe's attitude? A)Joe would love to use the new ball in future baseball games.
B) Joe would be happy as the new ball would have a faster acceleration.
C) Joe would be unhappy as the new ball would have a slower acceleration.
D) Joe's attitude would not change as there would be no change in the acceleration.
Chemistry
2 answers:
GarryVolchara [31]3 years ago
8 0

We know tha

Force = Mass X acceleration

acceleration = this provides the distance to the base ball

If mass of baseball is increased keeping force constant, the acceleration will decrease, this will decrease the distance traveled by the base ball

so Joe would be unhappy as the new ball would have a slower acceleration.

storchak [24]3 years ago
4 0
Try C that is what im going with
You might be interested in
Fireworks change (blank) into (blank) and (blank) energy.
Nitella [24]
Fireworks changes chemical energy into light energy

5 0
3 years ago
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer
lidiya [134]

The question is incomplete, the complete question is

Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V

Answer:

only IV and V

Explanation:

If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.

On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.

This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.

7 0
3 years ago
The change in enthalpy is the change in heat energy of a reaction and is calculated by (Hint: Hess' Law): Group of answer choice
Stolb23 [73]

Answer:

d. Sum of product enthalpies minus the sum of reactant enthalpies

Explanation:

The standard enthalpy change of a reaction (ΔH°rxn) can be calculated using the following expression:

ΔH°rxn = ∑n(products) × ΔH°f(products) - ∑n(reactants) × ΔH°f(reactants)

where,

ni are the moles of products and reactants

ΔH°f(i) are the standard enthalpies of formation of products and reactants

8 0
3 years ago
If 100 mg of ferrocene is reacted with 75 mg of anhydrous aluminum chloride and 40 microliters of acetyl chloride and 100 mg of
Alex_Xolod [135]

Answer:

81.3 %

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For ferrocene:-

Mass of ferrocene = 100 mg = 0.1 g

Molar mass of ferrocene = 186.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.1\ g}{186.04\ g/mol}

Moles\ of\ ferrocene= 0.0005375\ mol

For acetyl chloride:-

Volume = 40 microliters = 0.04 mL

Density = 1.1 g / mL

Density is defined as:-

\rho=\frac{Mass}{Volume}

or,  

Mass={\rho}\times Volume=1.1\times 0.04\ g=0.044 g

Mass of acetyl chloride = 0.044 g

Molar mass of acetyl chloride = 78.49 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.044\ g}{78.49\ g/mol}

Moles\ of\ acetyl\ chloride= 0.0005606\ mol

As per the reaction stoichiometry, one mole of ferrocene reacts with one mole of acetyl chloride to give one mole of monoacetylferrocene

Limiting reagent is the one which is present in small amount. Thus, ferrocene is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

one mole of ferrocene on reaction forms one mole of monoacetylferrocene

0.0005375 mole of ferrocene on reaction forms  0.0005375 mole of monoacetylferrocene

Moles of product formed =  0.0005375 moles

Molar mass of monoacetylferrocene = 228.07 g/mole

Mass of monoacetylferrocene produced = Moles*molecular weight = 0.0005375*228.07 g = 0.123 grams = 123 mg

Given experimental yield = 100 mg

<u>% yield = (Experimental yield / Theoretical yield) × 100 = (100/ 123) × 100 = 81.3 %</u>

5 0
3 years ago
Balance the following redox equation using the smallest integers possible and select the correct coefficient for the hydrogen su
goldfiish [28.3K]

Answer:

Coefficient of HSO_{3}^{-} is 5

Explanation:

Oxidation: MnO_{4}^{-}(aq)\rightarrow Mn^{2+}(aq)

  • Balance O and H in acidic medium: MnO_{4}^{-}(aq)+8H^{+}(aq)\rightarrow Mn^{2+}(aq)+4H_{2}O(l)
  • Balance charge : MnO_{4}^{-}(aq)+8H^{+}(aq)+5e^{-}\rightarrow Mn^{2+}(aq)+4H_{2}O(l) .............(1)

Reduction: HSO_{3}^{-}\rightarrow SO_{4}^{2-}

  • Balance O and H in acidic medium : HSO_{3}^{-}(aq)+H_{2}O(l)\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)
  • Balance charge : HSO_{3}^{-}(aq)+H_{2}O(l)-2e^{-}\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq) ..............(2)

[2\times eq(1)]+[5\times eq(2)] -

Balanced equation: 2MnO_{4}^{-}(aq)+5HSO_{3}^{-}(aq)+H^{+}(aq)\rightarrow 2Mn^{2+}(aq)+5SO_{4}^{2-}(aq)+3H_{2}O(l)

Coefficient of HSO_{3}^{-} is 5

8 0
3 years ago
Other questions:
  • A chemical reaction that has the general formula of nA ➡ (A)n is best classified as a ___________ reaction
    5·2 answers
  • When light bends around an object, the light is
    15·2 answers
  • Please help ill medal and fan!
    8·1 answer
  • What is an atom? the smallest particle of matter a piece of an element the smallest molecule in the universe a combination of pr
    5·1 answer
  • Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4 What volume of 1.45 M Ca(OH)2 is needed to react with 25.0 moles of H2SO4?
    12·1 answer
  • Help help help !!!!!!
    5·1 answer
  • What determines crystal size in minerals formed by lava or magma?
    6·1 answer
  • Complete the conceptap below . About Chemical Bonds ​
    6·1 answer
  • Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac
    13·1 answer
  • What is the electron configuration for an electrically neutral atom of beryllium (Be)?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!