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Klio2033 [76]
3 years ago
6

What is the predicted order of first ionization energies from highest to lowest for lithium (Li), sodium (Na), potassium (K), an

d rubidium (Rb)?
Chemistry
3 answers:
frutty [35]3 years ago
7 0
The first ionization energy is the energy that the atom lost its first electrons. The energy decrease and the atom is more reactive. So from highest to lowest is Li>Na>K>Rb.
Schach [20]3 years ago
6 0

Answer;

From highest to lowest is Li>Na>K>Rb.

Explanation;

- Ionization energy is the energy that is required to dislodge or remove an electron from the outer most energy level or energy shell. The first ionization energy is the energy required to remove the first electrons from the outermost energy shell.

- Lithium will have the highest first ionization energy, as the outer electron is closer to the pull of the nucleus and not shielded by full shells. This means that rubidium will be the lowest.


Firlakuza [10]3 years ago
5 0

Answer;

From highest to lowest is Li>Na>K>Rb.

Explanation;

- Ionization energy is the energy that is required to dislodge or remove an electron from the outer most energy level or energy shell. The first ionization energy is the energy required to remove the first electrons from the outermost energy shell.

- Lithium will have the highest first ionization energy, as the outer electron is closer to the pull of the nucleus and not shielded by full shells. This means that rubidium will be the lowest.


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In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?
Sauron [17]

Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

R_{eq}=R_1+R_2+....

For 17 light bulbs, the equivalent resistance is given by :

R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17

Hence, the total resistance is 17 ohms. Hence, the correct option is (d).

7 0
3 years ago
Describe the steps used to create Lewis dot structures to represent covalent bonds.
antiseptic1488 [7]
1)Identify the atoms that are participating in a covalent bond.
2)Draw each atom by using its element symbol. The number of valence electrons is shown by placing up to two dots on each side of the element symbol, with each dot representing a single valence electron.
3)Predict the number of covalent bonds each atom will make using the octet rule.
4)Draw the bonding atoms next to each other, showing a single covalent bond as either a pair of dots or a line representing a shared valence electron pair. If the molecule forms a double or triple bond, use two or three lines to represent the shared electron pairs, respectively.

5 0
3 years ago
Two or more assistance
Goryan [66]
I believe it would be a compound.
4 0
3 years ago
Looking at the Periodic Table, how can you determine if an element is a metal, metalloid or nonmetal?
Digiron [165]

Answer:

It depends on where it's located on the periodic table.

Explanation:

Metals are on left side of the periodic table except Hydrogen (H), which is a nonmetal, then there's the staircase, which has the metalloids, and on the right of the staircase are the nonmetals.

6 0
3 years ago
Which element is the excess reagent when 3.00 moles of Mg is ignited in 2.20 moles of pure oxygen
Artyom0805 [142]

Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

7 0
3 years ago
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