In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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Answer:
Change the temperature and pressure
Explanation:
In case we are analyzing the solubility of a salt in some solvent, raising the temperature would increase the solubility of a salt generally. In contrast, at lower temperatures the solubility of ionic salts would decrease.
Now, another variation of this scenario might be solubility of gases. According to Henry's Law, 
, meaning that the solubility of a gas is directly proportional to its partial pressure. Therefore, the greater the pressure, the greater the solubility of a gas.
To start one difference between the two is that a scientific experiment is meant to be repeated and to be formed into a theory and/or a scientific law. Scientific experiments also use different types of data, for instance, you could be recording how much a plant grows in a month, in an experiment you would focus on the types of soil being used. In an investigation you would observe how tall the plant actually grew.
