Current, resistance and voltage.
Answer:
Moles of carbon dioxide gas is 0.584 moles.
Mass of 0.584 moles of carbon dioxide gas is 25.7 g
Explanation:
Using ideal gas equation
PV = nRT
where,
P = Pressure of gas = 
V = Volume of gas = 30.0 L
n = number of moles of gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 27°C = 300.15 K
Putting values in above equation, we get:

Moles of carbon dioxide gas = 0.584 moles
Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g
The volume of the propane gas at standard pressure is 413861.25L.
The gas law needed to solve the volume of propane gas at standard pressure is Boyle's law.
<h3>Boyle's law</h3>
Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure, provided that the temperature remains contant.
Boyle's law can be expressed mathematically as
- P₁V₁ = P₂V₂............... Equation 1
Where:
- P₁ = Initial pressure of octane gas
- V₁ = Initial volume of octane gas
- P₂ = Final pressure of octane gas
- V₂ = Final volume of octane gas.
Since we were asked to find the final volume in the question above, we make V₂ The subject of the equation.
- V₂ = P₁V₁/P₂................... Equation 2
From the question,
Given:
- P₁ = 1.27 atm
- V₁ = 325875 L
- P₂ = 1 atm (Standard pressure)
Substitute the given values into equation 2
- V₂ = (1.27×325875)/1
- V₂ = 413861.25 L.
Hence, the volume of the propane gas at standard pressure is 413861.25L.
Learn more about Boyle's law here: brainly.com/question/26040104