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juin [17]
4 years ago
12

The average business traveler spends almost $50 per day. Mary O Sullivan spent the following yesterday: dinner, $21.50; lunch, $

10.58; breakfast, $5.88; tips, $7.51; and taxes, $2.95. how much was she under the average?
Mathematics
1 answer:
taurus [48]4 years ago
3 0

To solve this, we simply add up the total amount of money she spent that day:

21.50 + 10.58 + 5.88 + 7.51 + 2.95 = 48.42

50 - 48.42 = 1.58

She was $1.58 under the average.

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Solve the inequality 0<5x-2<8
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Answer:

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Patrick earns $40 per hour. He earned an extra $1000 for working on a special project. His pay check for the month was 7420. How
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Patrick worked 160.5 hours because you have to subtract 1000 from 7420 then divide that by 40 for your answer. Also, Patrick has a sweet job.
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Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have
koban [17]
I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3.... 

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5 0
3 years ago
An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn
elixir [45]
  • The first four terms are : 15000, 14850, 14700, 14550
  • a = 15000 ; d = -150
  • The explicit formula is : a_{n} =  - 150n \:  + 15150

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

a_{n} \:  = nd \: + c

For n = 1

15000 = 1( - 150)  + c

15000 =  - 150 + c

c = 15150

Hence, the explicit formula for the nth term is :

a_{n} \:  =  - 150n \:  + 15150

Learn more : brainly.com/question/12006170

3 0
3 years ago
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

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u'=u^2-1

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\dfrac{u'}{u^2-1}=1

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\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

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u=\dfrac2{1-Ce^{2t}}-1

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y=\dfrac2{1-Ce^{2t}}-1-t

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y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

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3 0
3 years ago
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