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Brrunno [24]
4 years ago
13

Which is the exponential form of log3 x= 11?

Mathematics
1 answer:
Neporo4naja [7]4 years ago
6 0

Answer:

x = 3^{11}

Step-by-step explanation:

relation between logarithmic and exponential form is given by

\log_a x = y \\ is same as a^y = x where a>0 and a is not equal to 1.

____________________________________________

\log_3 x = 11 \\\\x = 3^{11}

Thus, exponential form is x = 3^{11}

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natulia [17]
The answer is 3 because it goes into 39 and 42 and 6 doesn't go into 39
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The principal at Riverside High School would like to estimate the mean length of time each day that it takes all the buses to ar
Lilit [14]

Answer:

C) 11

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    

And on this case we have that ME =7 and we are interested in order to find the value of n, if we solve n from the last equation we got:

n=(\frac{z_{\alpha/2} s}{ME})^2  

And replacing the values that we got we have:

n=(\frac{1.64(14)}{7})^2 =10.758 \approx 11

C) 11

8 0
4 years ago
Help!!! I don’t get this
saveliy_v [14]

S, sample space :

all the possible outcomes of an experiment

number × sampel space = 8

Answer :

D. HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

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7 0
3 years ago
What is the solution set of the following equation?
wel

\dfrac{4}{5}x^2=2x-\dfrac{4}{5}\ \ \ |\cdot5\\\\4x^2=10x-4\ \ \ |-10x\\\\4x^2-10x=-4\ \ \ \ |+4\\\\4x^2-10x+4=0\ \ \ |:2\\\\2x^2-5x+2=0\\\\2x^2-x-4x+2=0\\\\x(2x-1)-2(2x-1)=0\\\\(2x-1)(x-2)=0\iff2x-1=0\ \vee\ x-2=0\\\\x=\dfrac{1}{2}\ \vee\ x=2\\\\Answer:\ \left\{2;\ \dfrac{1}{2}\right\}

4 0
4 years ago
3
Alex787 [66]

Answer:

Option 1 is correct i.e.

(\frac{2^3\:\textbf{.}\:3^0}{5})^2=\frac{2^6.1^2}{5^2}=\frac{64}{25}

Step-by-step explanation:

We need to simplify the expression: (\frac{2^3\:\textbf{.}\:3^0}{5})^2

We know that: (a^m)^n= a^{m*n} and a^0=1

We would use these exponent laws to solve our question.

First we will apply a^0=1

(\frac{2^3\:\textbf{.}\:3^0}{5})^2\\=(\frac{2^3\:\textbf{.}\:1}{5})^2\\

Now, we will apply (a^m)^n= a^{m*n}

=\frac{(2^3)^2\:\textbf{.}\:1^2}{5^2}\\=\frac{2^6\:\textbf{.}\:1}{5^2}\\=\frac{64}{25}

So, the result is: \frac{64}{25}

Therefore, Option 1 is correct i.e.

(\frac{2^3\:\textbf{.}\:3^0}{5})^2=\frac{2^6.1^2}{5^2}=\frac{64}{25}

7 0
3 years ago
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