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SCORPION-xisa [38]
3 years ago
8

You must drink 16 oz of Gatorade every 15 minutes of aerobic exercise in order to achieve benefits

Physics
2 answers:
damaskus [11]3 years ago
5 0
I know my answer is late, but for future visitors:
False, you do not need to drink 16 oz of Gatorade every 15 minutes of aerobic exercise in order to achieve benefits.
Mekhanik [1.2K]3 years ago
3 0
<span>False. Water is the best and the only hydrating property that should be consumed prior to any exercise. Gatorade is good to take while doing exercise or after to give you a boost of energy but should never be consumed excessively. These drinks can increase your heart rate and in my opinion are no substitute for water.</span>
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49. A 6.1-kg bowling ball is liſted 2.1 m to a shell. Find
stealth61 [152]

Answer:

125.5J

Explanation:

Given parameters:

Mass of the bowling ball  = 6.1kg

Height of lifting  = 2.1m

Unknown:

Increase in the ball energy  = ?

Solution:

The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.

 Potential energy  = mgh

     m is the mass

     g is the gravity  

     h is the height

Now insert the given parameters and solve;

       Potential energy  = 6.1 x 9.8 x 2.1  = 125.5J

5 0
3 years ago
An airplane during departure has a constant acceleration of 3 m / s².
Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>

t

3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>

8

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

6 0
3 years ago
A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat
Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

s = v_0t + gt^2/2

where v_0 is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

3.5 = v_01.1 - 9.81*1.1^2/2

3.5 = 1.1v_0 - 5.94

1.1v_0 = 3.5 + 5.94 = 9.44

v_0 = 9.44 / 1.1 = 8.58 m/s

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s

So they keys would have a downward speed of 2.211 m/s

5 0
3 years ago
Review Conceptual Example 7 before starting this problem. A uniform plank of length 5.0 m and weight 225 N rests horizontally on
Andreas93 [3]

Answer:

0.82 m

Explanation:

We are given that

Weight,w_1=225 N

Length,l=5 m

d=1.1 m

We have to find the distance x  for which person weighs 385 N walk on the overhanging part of the plank before it just begins to tip.

Half length=\frac{l}{2}=\frac{5}{2}=2.5 m

r=\frac{l}{2}-d=2.5-1.1=1.4 m

w_2=385 N

When system in equilibrium then

w_1r=w_2 x

225\times 1.4=385\times x

x=\frac{225\times 1.4}{385}

x=0.82 m

6 0
4 years ago
Under what conditions will a moving 0.030 kg marble and a moving 2.43 kg rock have the same kinetic energy
Anestetic [448]

Answer:

To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Explanation:

The general formula of kinetic energy is given as follows:

K.E = \frac{1}{2}mv^{2}

where,

K.E = Kinetic Energy

m = mass of the object

v = speed of the object

So, for the marble and rock to have same kinetic energy, we can write:

K.E_{marble} = K.E_{rock}\\\\\frac{1}{2}m_{marble}v_{marble}^{2} =  \frac{1}{2}m_{rock}v_{rock}^{2}\\\\(0.03\ kg)v_{marble}^{2} = (2.43\ kg)v_{rock}^{2}\\\\taking\ square\ root\ on\ both\ sides:\\v_{marble} = \sqrt{\frac{2.43\ kg}{0.03\ kg}}v_{rock}\\\\v_{marble} = 9\ v_{rock}

<u>Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.</u>

4 0
3 years ago
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