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Papessa [141]
3 years ago
15

20. Unlike other kinds of liquids, volatile liquids

Physics
1 answer:
Nana76 [90]3 years ago
5 0
What's is the question asking, true or false?
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Which of the following is NOT accelerating?
ivolga24 [154]
I would say the answer to your question is A Ferris wheel turning at a constant speed. The reasoning behind this answer is the fact that traveling in a constant direction at a constant speed is not accelerating. The Ferris wheel is the only option that fits this description. The last option would be incorrect due to independent causes such as speed limit changes as well as turns and stops on the highway.
7 0
3 years ago
A 30000 grams boy is riding a merry-go-round with a radius of 600 cm. What is the centripetal force and acceleration on the boy
irga5000 [103]

Answer:

centripetal force is calculated by mass(kg) × tangetial velocity(m/s) ÷ radius (m)

Explanation:

so 30000g= 30kg

50km/h = 13.88m/s

600cm= 6m

30×13.88÷6= 69.4N

N= Newton's

hope this helps.

btw I'm 16 and love physics so I tried my best in this hope it went well!!

7 0
3 years ago
An element from group 2 on the periodic table will bond lonically with elements from group 17(7A)
Natalija [7]

Answer:

Elements in group IIA have 2 electrons in their outermost shell so they can donate these electrons of group VII A which have seven electrons in their outermost shell. So it is necessary 2 elements of group VII A, each atoms accepts one electron.

Explanation:

8 0
3 years ago
A 7.80 g bullet moving at 530 m/s penetrates a tree trunk to a depth of 5.40 cm. (a) Use work and energy considerations to find
True [87]

Answer:

a) F=20287.22N

b) t=2*10^-4s

Explanation:

E=1/2*m*v^2=0.5*7.8*10^-3kg*(530m/s)^2=1095.51J

The frictional force's work must be equal than the energy to stop the bullet.

So: W=F*d=F*0.054m=1095.51J, F=20287.22N

Considering the frictional force is constant, the bullet moves with constant aceleration.

a=F/m=20287.22N/7.8*10-2kg=2.6*10^6m/s^2

then d(t)=Vt-1/2*a*t^2,

5.4*10^-2m=530m/s*t-1.3*10^6m/s^2*t^2

I will calculate the time using the cuadratic formula:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

with a=1.3*10^6, b=-530, c=5.4*10^-2

t=2*10^-4s

8 0
2 years ago
If vector A=2i+3j-k and vector B=4i+6j-2k. The angle between them will be: a) 0°b)45°c)90°d)60°​
melomori [17]

Notice that

<em>B</em> = 4<em>i</em> + 6<em>j</em> - 2<em>k</em> = 2 (2<em>i</em> + 3<em>j</em> - <em>k</em>) = 2<em>A</em>

so both vectors point in the same direction and the angle between them is (A) 0°.

7 0
3 years ago
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