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nirvana33 [79]
2 years ago
15

An airplane during departure has a constant acceleration of 3 m / s².

Physics
1 answer:
Rama09 [41]2 years ago
6 0

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>

t

3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>

8

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

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Answer:

Right

Explanation:

electromagnetic waves can travel through space (a vacuum) because it doesn't need a medium and its particles to propagate whereas a mechanical wave needs a medium to propagate. For example sound is a mechanical wave, sound vibrates off a mediums particles to propagate and for sound to be heard and travel

7 0
3 years ago
During which moon phase do spring tides occur?
Murrr4er [49]

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The Full Moon and New Moon

Explanation:

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A parallel-plate capacitor has a plate area of 0.2 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magni
barxatty [35]

Answer:

The potential difference across the plates is 226 V.

Explanation:

Given;

area of the capacitor plate, A = 0.2 m²

separation, d = 0.1 mm = 0.1 x 10⁻³ m

charge on each plate, Q = 4 x 10⁻⁶ C

Charge on the capacitor is given by;

Q = CV

Where;

C is the capacitance of the capacitor, given as;

C = ε₀A / d

Then, the potential difference across the plates is given by;

V = \frac{Q}{C} = \frac{Qd}{\epsilon_o A} = \frac{(4*10^{-6})(0.1*10^{-3})}{(8.85*10^{-12})(0.2)}\\\\V = 226 \ V

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5 0
3 years ago
Why would an orange roll of your cafeteria tray if you stopped suddenly
Vikentia [17]
Because the frictional force between the orange skin peel is great enough when you are walking for it to be carried on the tray, along with the gravitational force downwards onto the tray. When you stop, the force that you exerted moving forward it the same as on the tray and on the orange. So when you stop, the force is still on the orange as the same velocity as your we’re traveling, while the tray and you stop.
6 0
3 years ago
An undamped 1.48 kg horizontal spring oscillator has a spring constant of 35.4 N/m. While oscillating, it is found to have a spe
givi [52]

Answer: 0.798 m

Explanation:

Given

Mass of the spring oscillator, m = 1.48 kg

Force constant of the spring, k = 35.4 N/m

Speed of oscillation, v = 3.9 m/s

Kinetic Energy = 1/2 mv²

Kinetic Energy = 1/2 * 1.48 * 3.9²

KE = 0.5 * 22.5108

KE = 11.26 J

Using the law of conservation of Energy. The Potential Energy of the system is equal to Kinetic Energy of the system

KE = PE

PE = 1/2kx²

11.26 = 1/2 * 35.4 * x²

11.26 = 17.7x²

x² = 11.26 / 17.7

x² = 0.6362

x = √0.6362

x = 0.798 m

5 0
3 years ago
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