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Tanya [424]
3 years ago
5

You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th

e right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.
Find the sun of the force on the self

Determine the acceleration of the sled

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?
Physics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

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According to Hooke's law, the force necessary to stretch or compress a spring is proportional to what value?
ankoles [38]

Answer:

displacement

Explanation:

Hookes Law describes the elastic properties of materials only in the range in which the force and displacement are proportional (displacement = change in length).

8 0
3 years ago
If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s , determine the constant deceleration of the car
Svetlanka [38]

Question:  Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.

Answer:

1.29 m/s²

Explanation:

From the question,

a = (v-u)/t............................ Equation 1

Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

Given: v = 13 m/s, u = 35 m/s, t = 17 s.

a = (13-35)/17

a = -22/17

a = -1.29 m/s²

Hence the deceleration of the car is 1.29 m/s²

8 0
3 years ago
The siren of an ambulance wails at 1395 Hz when the ambulance is stationary. What frequency will you hear after this ambulance p
Alja [10]

Answer: the frequency observed will be 1269.45hz

Explanation: according to the doppler effect,

Apparent frequency f' = (c/(c+u))*f

f = real freq of sound of moving sound source

c = speed of sound in air

u = speed of moving sound source

f' = (343/(343+33.6))*1395

f' = 1269.45hz

3 0
3 years ago
You have 13.0 gallons of gasoline. How many liters is this? (1 gallon equals<br> about 3.79 L.)
Harlamova29_29 [7]

Answer:

I believe the answer is C

Explanation:

8 0
4 years ago
Read 2 more answers
A 75 kg bungee jumper leaps from a bridge. When he is 30 meters above the water, and moving at a speed of 20 m/s, the bungee cor
jasenka [17]

Answer:

k = 52.2 N / m

Explanation:

For this exercise we are going to use the conservation of mechanical energy.

Starting point. When it is 30 m high

        Em₀ = K + U = ½ m v² + m g h

Final point. Right when you hit the water

        Em_{f} = K_{e} = ½ k x²

in this case the distance the bungee is stretched is 30 m

        x = h

as they indicate that there are no losses, energy is conserved

        Em₀ = Em_{f}

       ½ m v² + m g h = ½ k h²

       k = \frac{m (v^{2} + 2 g h)}{h^{2} }

let's calculate

       k = \frac{75 \ ( 20^{2}  + 2 \ 9.8 \ 30)}{30^{2} }

       k = 52.2 N / m

3 0
3 years ago
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