Answer: She attended to 7 weekday games.
Step-by-step explanation:
Let's denote our variables as:
Wd = number of weekday games that she attended.
We = number of weekend games that she attended.
We know that in total, she attended to 23 games, so we have:
Wd + We = 23.
"If Ariel attended nine more weekend games than weekday games" can be written as:
We = Wd + 9.
Then we have the system of equations:
Wd + We = 23.
We = Wd + 9.
The first step would be to replace the second equation into the first one, as:
Wd + We = 23.
Wd + (Wd + 9) = 23
Now we can solve this for Wd.
2*Wd + 9 = 23
2*Wd = 23 - 9 = 14
Wd = 14/2 = 7
She attended to 7 weekday games.
And:
We + 7 = 23
We = 23 - 7 = 16
She attended at 16 weekend games.
Answer:
○ 4⁵\4²
Step-by-step explanation:
1. According to the Quotient-to-Power Exponential Rule, whenever you divide terms with exponents and coefficients, you subtract the exponents:
4²\4⁵ = 4⁻³
3. According to the Negative Exponential Rule [Reverse], you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM POSITIVE TO NEGATIVE:
b⁻ⁿ = 1\bⁿ
However, according to the Negative Exponential Rule, you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM NEGATIVE TO POSITIVE:
bⁿ = 1\b⁻ⁿ
Anyway, this is what you get using this exponential:
1\4³ = 4⁻³
4. Back to what I said about the <em>Quotient-to-Power</em> Exponential Rule, you subtract the exponents, but in this case, doing that will give you 4³. This is the ONLY uniqueness, while the rest of them are 4⁻³.
I am joyous to assist you anytime.
Hi!
If im reading this right, and im not sure i am, it would be 9100.
Sorry if its wrong!
Hope this helps!
<h2><em>~~PicklePoppers~~</em></h2>
Answer:
A. is the correct one. The statement makes sense.
Step-by-step explanation:
A. This is true because if you make your graph starting from the lowest value then the graph will use more space to fit the data and it will make it look bigger. Also, the variation will seem higher because it will feel that you are increasing it from 0, so the relative increase will be higher.
B. Reducing the range of the vertical axis will increase the relative size of variation, not make it decrease, as we explained in A.
C. Even though it is technically certain that the data shown is the same as before, the way to show data also matters. And by making changes on the presentation of your data you can obtain different results on the impression that leaves to people.
D. This is just false, because you are indeed dereasing the range of the vertical axis, not increasing it.
The area of a circle is A = πr^2. We let A1 And A2 the areas of the circles and r1 and r2 the radius of each, respectivley.
A1 + A2 = 80π
Substitute the formula for the area,
π(r1)^2 + π (r2)^2 = 80π
From the statement, we know that r2=2(r1).
<span>π(r1)^2 + π (2 x r1)^2 = 80π
</span>We can cancel π, we will have
5 x (r1)^2 = 80
Thus,
r1 = 4 and r2 = 8
