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3 years ago

The sum of the areas of two circles is 80 pi

1 answer:

5 0

The area of a circle is A = πr^2. We let A1 And A2 the areas of the circles and r1 and r2 the radius of each, respectivley.

A1 + A2 = 80π
Substitute the formula for the area,
π(r1)^2 + π (r2)^2 = 80π

From the statement, we know that r2=2(r1).

<span>π(r1)^2 + π (2 x r1)^2 = 80π
</span>We can cancel π, we will have

5 x (r1)^2 = 80
Thus,

r1 = 4 and r2 = 8

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If f(x) = 4x^2 and g(x) = x+1, find (f.g)(x).

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Answer:

4x^3 + 4x^2

Step-by-step explanation:

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3 years ago

The sum of two negative integers is a negative integers

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2 years ago

How do I solve x(3x-17)=0 using the square root property

scZoUnD [109]

Answer:

x = 0 or $x = \frac{17}{3}$

Step-by-step explanation:

We have the quadratic equation of variable x and we have to solve the equation using the square root property.

Now, we have x(3x - 17) = 0

⇒ 3x² - 17x = 0

⇒ $3(x^{2} - \frac{17}{3}x ) = 0$

⇒ $x^{2} - 2 \times (\frac{17}{6}) \times x + (\frac{17}{6} )^{2} = (\frac{17}{6} )^{2}$

⇒ $(x - \frac{17}{6})^{2} = (\frac{17}{6} )^{2}$

Now,square rooting both sides we get,

$x - \frac{17}{6} = \pm\frac{17}{6}$

Therefore, either x = 0 or $x = \frac{17}{3}$ (Answer)

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2 years ago

How can we tell if a number is divisible by 4

Elza [17]

Answer: You take the last two digits of the original number and see if they are divisible by 4.

Step-by-step explanation: Take your original number and find the last two digits. If they are divisible by 4, then the original number is divisible by 4.

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3 years ago