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4 years ago

To turn 25% into a decimal

Mathematics

1 answer:

Ray Of Light [21]4 years ago

4 0

25% = $\frac{25}{100} =0.25$

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3 years ago

The product of two positive numbers is 1,800. One number is twice the other number. The equation to determine the two numbers, w

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600

Step-by-step explanation:

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3 years ago

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One-fourth of the residents of a particular community leave their garage doors unlocked when they go out to do an errand. The lo

Inessa [10]

Answer:

Required Probability = 0.625

Step-by-step explanation:

Given,

Probability of unlocked doors, P(U) = 0.25

Probability of locked doors, P(U') = 0.75

Probability of something being stolen when door is unlocked, P(S/U) = 0.05

Probability of something not being stolen when door is unlocked, P(S'/U) = 0.95

Probability of something being stolen when door is locked, P(S/U') = 0.01

Probability of something not being stolen when door is locked, P(S'/U') = 0.99\

probability of being stolen either door is locked or not,

P(S) =P(S/U).P(U) + P(S\U').P(U')

= 0.05 x 0.25 + 0.95 x 0.75

= 0.0125 + 0.0075

= 0.02

Probability that door was unlocked when while steeling can by given by

$P(U/S)\ =\ \dfrac{P(S/U).P(U)}{P(S)}$

$=\ \dfrac{0.05\times 0.25}{0.02}$

= 0.625

hence, the required probability is 0.625.

7 0

3 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Veseljchak [2.6K]

Answer:

$1)\\\large\boxed{x=\dfrac{a+c}{b},\ if\ b\neq0}\\\\2)\\\boxed{if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number}\\\\\boxed{if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)}$

Step-by-step explanation:

$1)\\a-(a+b)x=(b-a)x-(c+bx)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\a-ax-bx=bx-ax-c-bx\qquad\text{cancel}\ bx\ \text{on the right side}\\\\a-ax-bx=-ax-c\qquad\text{add}\ ax\ \text{to both sides}\\\\a-bx=-c\qquad\text{subtract}\ a\ \text{from both sides}\\\\-bx=-a-c\qquad\text{divide both sides by}\ -b\neq0\\\\x=\dfrac{-a-c}{-b}\\\\x=\dfrac{a+c}{b}$

$2)\\2(3x-5a)+9(2a-7b)+3(5a-2x)=0\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(3x)+(2)(-5a)+(9)(2a)+(9)(-7b)+(3)(5a)+(3)(-2x)=0\\\\6x-10a+18a-63b+15a-6x=0\qquad\text{combine like terms}\\\\(6x-6x)+(-10a+18a+15a)-63b=0\\\\23a-63b=0\qquad\text{add}\ 63b\ \text{to both sides}\\\\23a=63b\qquad\text{divide both sides by 23}\\\\a=\dfrac{63b}{23}\\\\if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number\\\\if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)$

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4 years ago

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I believe it’s A! But double check just to be sure

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3 years ago

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