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dybincka [34]
3 years ago
15

Tanya has a garden with a trench around it. The garden is a rectangle with length 212m2 \dfrac12 \text{m} 2 2 1 ​ m 2, start fra

ction, 1, divided by, 2, end fraction, start text, m, end text and width 2 m2 \text{ m} 2 m 2, start text, space, m, end text . The trench and garden together make a rectangle with length 312m3 \dfrac12 \text{m} 3 2 1 ​ m 3, start fraction, 1, divided by, 2, end fraction, start text, m, end text and width 3 m3 \text{ m} 3 m 3, start text, space, m, end text .
Mathematics
1 answer:
zysi [14]3 years ago
4 1

Answer:

Tanya has a garden with a trench around it. The garden is a rectangle with length 212m2 \dfrac12 \text{m} 2 2 1  m 2, start fraction, 1, divided by, 2, end fraction, start text, m, end text and width 2 m2 \text{ m} 2 m 2, start text, space, m, end text . The trench and garden together make a rectangle with length 312m3 \dfrac12 \text{m} 3 2 1  m 3, start fraction, 1, divided by, 2, end fraction, start text, m, end text and width 3 m3 \text{ m} 3 m 3, start text, space, m, end text

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ANSWER

EXPLANATION

For each of the three events, there are 8 possible outcomes, so the probability of each event is,

P(event)=\frac{favorable\text{ }outcomes}{possible\text{ }outcomes}=\frac{favorable\text{ }outcomes}{8}

• Event A:, there must be only odd numbers in the last two rolls, which are either ,EOO or OOO,. This event has 2 favorable outcomes, ,so its probability is 1/4,.

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• Event B,: this is the complementary event to event A. Here the last two rolls must be even numbers - both or only one of the last two: ,OOE, EEO, EOE, OEE, EEE, OEO,. This event has 6 favorable outcomes, so ,its probability is 3/4,.

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• Event C,: this event is when the first and last rolls are even numbers in the same event. This is either ,EOE or EEE,. Since this event has 2 favorable outcomes, ,its probability is 1/4,.

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oshua tracks the points he scores in 10 basketball games. In two games Joshua scored 8 points each, in one game he scored 3 poin
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