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2 years ago

Help..... me .......please..........ITS URGENT

Mathematics

1 answer:

Vikentia [17]2 years ago

6 0

Answer: 115, 2645

(x= 115, y= 2645)

Step-by-step explanation:

There are two methods to this, which is using the graph with each x and y value, or substituting in values.

I would suggest looking at the graph first and then substituting values so you know the equation is being satisfied by the ordered pair.

In this case, one way to check it could look like this (substituting y value):

y = 23x

2645 = 23x

x = 2645÷23

x = 115

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.

nekit [7.7K]

Answer:

a) $S= {HH, HT, TH, TT}$

b) $P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is $2^2 = 4$

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

$S= {HH, HT, TH, TT}$

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

$P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

5 0

3 years ago

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ra1l [238]

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Svetlanka [38]

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4 years ago

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lozanna [386]

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3 years ago

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fgiga [73]

Answer:

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