Answer:
The new molarity is 0.614 M
Explanation:
Formula for dilutions is:
M concentrated . Volume of conc = Volume of dil . M diluted
6.54 M . 249 mL = 416 mL . M diluted
Notice that volume of diluted is = Initial volume + What we added of water
(249mL + 167 mL)
(6.54 M . 249 mL) / 416mL = M diluted → 0.614 M
Answer:
The exceptions to the periodic trends in ionization energy are the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.
Explanation:
Taking a close look at the figure of first ionization energies, it clearly shows that the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.
This is as a result of Hund's rule and electron configuration. For example, the first ionization potential electron of beryllium is obtained from a 2s orbital while that of boron comes from a 2p electron. However, for oxygen and nitrogen, their electrons are obtained from 2p orbitals. While spin is uniform for all 2p electrons of nitrogen, it is different for oxygen.
The SI unit of specific heat is J per gram per degree
Celsius. Thus it follows that specific heat could be calculated in this way:
Specific Heat = Energy / (mass x change in temperature)
Thus,
Specific Heat = 3.912 cal / (9.84 oz x (191.2 ˚F – 73.2 ˚F))
Specific Heat = 3.369 x 10^-3 cal/oz-˚F
Answer:
0.049 mol/L.s
Explanation:
The decomposition of hydrogen peroxide is:
![Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%202%20%20%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D)
The rate of decomposition reaction = the rate of formation of 
= 0.098 mol/L.s
∴
Rate of formation of 
= 0.049 mol/L.s
Mg(NO3)2
Mg is +2 in oxidation while NO3 is -1, so you require two NO3 to have a neutral charge: 0
