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Softa [21]
3 years ago
8

Write a balanced half-reaction for the oxidation of gaseous nitric oxide to aqueous nitrous acid in acidic aqueous solution. Be

sure to add physical state symbols where appropriate.
Chemistry
1 answer:
Bad White [126]3 years ago
4 0

Explanation:

Reaction for oxidation of gaseous nitric oxide to aqueous nitrous acid is as follows.

            NO(g) \rightarrow HNO_{2}(aq)

By adding water, we will balance the oxygen atoms on both the sides as follows.

          NO(g) + H_{2}O(l) \rightarrow HNO_{2}(aq)

Now, we will balance the hydrogen atoms by adding H^{+} ions as follows.

         NO(g) + H_{2}O(l) \rightarrow HNO_{2}(aq) + H^{+}(aq)

Now, we will add OH^{-} ions on both the sides in order to neutralize H^{+} ions.

      NO(g) + H_{2}O(l) + OH^{-}(aq) \rightarrow HNO_{2}(aq) + H^{+}(aq) + OH^{-}(aq) ..... (1)

We will combine the H^{+} and OH^{-} ions in order to form water in equation (1) and cancelling the common terms as follows.

            NO(g) + OH^{-}(aq) \rightarrow HNO_{2}(aq)

Now, we will balance the charge on both the sides as follows.

         NO(g) + OH^{-}(aq) \rightarrow HNO_{2}(aq) + 1e^{-}

Thus, we can conclude that the balanced half-reaction equation is as follows.

         NO(g) + OH^{-}(aq) \rightarrow HNO_{2}(aq) + 1e^{-}

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PLEASE HELP WILL GIVE BRAINLIEST
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3 years ago
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

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#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil
Lynna [10]

Answer:

<h2>0.93 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 37.2 g

volume = 40 mL

We have

density =  \frac{37.2}{40}  \\  = 0.93

We have the final answer as

<h3>0.93 g/mL</h3>

Hope this helps you

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3 years ago
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