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3 years ago

What type of factors affect the speed of light? explain

Chemistry

1 answer:

Lina20 [59]3 years ago

4 0

Answer:The speed of a wave is dependant on four factors: wavelength, frequency, medium, and temperature.

Explanation:

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4. Consider a 33.0 mL solution containing 0.0758 M NaF and 0.0955 M HF. What is the total number of moles of HF after the additi

Ostrovityanka [42]

Buffer solution resist the change in pH upon addition of small amount of strong acid or strong base.
Buffer consists of weak acid as HF / and its conjugate base NaF
When strong acid as HCl is added to buffer, it respond with its conjugate base to convert the strong acid to weak acid like this:
HCl (S.A) + NaF → NaCl + HF (W.A)
moles of HF we already have = M * V(in liters)
= 0.0955 M * 0.033 L = 3.15 x 10⁻³ mole
moles of HCl added = 8.00 x 10⁻⁵ mole
one mole HCl reacts with 1 mole NaF to give 1 mole HF
so the amount added to HF = 8.00 x 10⁻⁵
Total moles of HF present = (3.15 x 10⁻³) + (8.00 x 10⁻⁵) = 3.23 x 10⁻³ mole

4 0

3 years ago

How much heat (in kilojoules) is evolved or absorbed in the reaction of 1.90 g of na with h2o? 2na(s) 2h2o(l)→2naoh(aq) h2(

myrzilka [38]

Do you have a screen shot or picture of the problem?

3 0

3 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

3 years ago

A 23.9g object was submerged into 50.5ml of water. If the water rose to 89.4ml then what is the object's density?

timama [110]

Answer:

50.2

Explanation:

4 0

2 years ago

Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide in part 1. In part 2

ipn [44]

Answer:

The major product formed is a benzyl allyl compound, namely 2-methylene propylbenzene

Explanation:

The product formed from this Wittig reaction with phosphonium ylide is a phenylallyl compound, 2-methylene propylbenzene. Structure and reaction synthesis is attached in file.

The types of transformation involved are:

alkylation (as there is a transfer of alkyl group)
addition (reaction of ylide)

5 0

2 years ago

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