Answer:
2.5 moles of Al
Explanation:
We'll begin by calculating the number of mole in 127 g of Al₂O₃. This can be obtained as follow:
Mass of Al₂O₃ = 127 g
Molar mass of Al₂O₃ = 101.961 g/mol
Mole of Al₂O₃ =?
Mole = mass / molar mass
Mole of Al₂O₃ = 127 / 101.961
Mole of Al₂O₃ = 1.25 mole
Finally, we shall determine the number of mole of Al that reacted. This can be obtained as follow:
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above,
4 moles of Al reacted to produce 2 moles of Al₂O₃.
Therefore, Xmol of Al will react to produce 1.25 moles of Al₂O₃ i.e
Xmol of Al = (1.25 × 4)/2
Xmol of Al = 2.5 moles.
Thus, 2.5 moles of Al is needed for the reaction.
This is called a combustion reaction. A combustion reaction involves oxygen gas. Most combustion reaction are exothermic as they give off heat. When organic molecules (containing carbon and hydrogen) combust the reaction products are carbon dioxide and water as well as heat or light. Combustion reactions may be complete or incomplete, a complete combustion releases more energy than incomplete combustion.
Answer:
3300.85 g
Explanation:
Given data:
Mass of ZnCl₂ produced = ?
Mass of H₂ produced = 49.8 g
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of H₂:
Number of moles = mass/molar mass
Number of moles = 49.8 g/ 2.056 g/mol
Number of moles = 24.22 mol
Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.
H₂ : ZnCl₂
1 : 1
24.22 : 24.22
Mass of ZnCl₂:
Mass = number of moles × molar mass
Mass = 24.22 × 136.286 g/mol
Mass = 3300.85 g
Answer:
An ionic bond is an attraction between ions of opposite charge in an ionic compound.
