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2 years ago

1. g(x) = -4x + 1 Find the inverse

Mathematics

1 answer:

Gwar [14]2 years ago

8 0

I took a picture because I had solved it on paper , but here you go .

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The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

3 years ago

Perpendicular lines are always, sometimes , never coplanar

daser333 [38]

They are always on a coplanar

8 0

2 years ago

Read 2 more answers

A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel.

Vladimir79 [104]

Centre angle will be 360° as its totally a circle.

radius=r=25ft

Angle between two cars=360/20=18°

Arc length=L

$\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)$

$\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))$

$\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)$

$\\ \sf\longmapsto L=2.5\pi ft$

Now

Area be A

$\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2$

$\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2$

$\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}$

$\\ \sf\longmapsto A=1562.5\pi/2$

$\\ \sf\longmapsto A=781\pi ft^2=$

4 0

2 years ago

The mass of the sun is 21.3525×102921.3525×1029 kg. the mass of mercy is 328.5×1021328.5×1021 kg.how many times larger is the ma

Liono4ka [1.6K]

This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.

Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>

8 0

3 years ago

The figure shows the letter T and four of its transformed images -A, B, C, and D:

laila [671]

Answer:

Come all bad girls to see and show

see d and show b and p

bqn-fozw-cbf

5 0

2 years ago