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3 years ago

11

If a + bi is a zero of a function and the coefficients of the polynomial are real, what will be the other complex zero of the fu

nction?

1 answer:

lukranit [14]3 years ago

8 0

A - bi would be the other complex zero.
When you take the sqrt when solving an equation you get a + and - solution.

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Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

3 years ago

The absolute value of 7<br><br>−12<br><br>is

MakcuM [25]

Answer:

7

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

More points for my easy questions (fair deal)

Grace [21]

Answer:

D

Step-by-step explanation:

The thing that is being cubed here is the sum of x and 4, not x or 4 individually. After you have taken care of what is in parentheses, you add 3x, which gives the sum of x+4 cubed and 3x. Hope this helps!

5 0

3 years ago

Read 2 more answers

URGENT<br> I put an answer already but I need a confirmation!

Orlov [11]

Answer:

I think number one is B. I also think number two is D.

4 0

3 years ago

A sixth grade student bought three cans of tennis balls for $4 each. Sales tax for all three cans with $0.95. Write an expressio

Murrr4er [49]

F(x) = 4x + 0.95

Hope this helps!!

4 0

3 years ago