Answer: I don’t think I understand can you set this up differently so I can answer this please
Step-by-step explanation:
X 0 y was 30
at x 12 y is about 55
12-0 = 12
55-30 = 25
25/12 = 2.08 inches per year average
so answer should be D
Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
Answer: im not sure if there was supposed to be more to this problem, like how much dough was needed before 35% of the pie was eaten???? (if there is more pls comment and ill help)
Answer:
The experimental probability would be equal to the number of times the event happened over the number of times it was attempted. In this case, the experiment was tried 48 times, and only 6 times did it land on 2. The experimental probability is 6/48, which simplified to 1/8.
