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miv72 [106K]
3 years ago
8

the pet store sells bags of pet food. there are 4 bags of cat food. one sixth of the bags of food are bags of cat food. how many

bags of pet food does the pet store have?
Mathematics
2 answers:
const2013 [10]3 years ago
8 0
28 bags if you include the cat food (which you would)
ludmilkaskok [199]3 years ago
3 0
The answer is 24.

Work:
4 x 6=24

4=cat food bags
6=denominator of fraction
24=total bags of food
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Chad is eating a 50-gram chocolate bar which contains 30% cocoa. How many grams of cocoa are in the chocolate bar?
Allushta [10]

Answer: 15 grams

If he had 100 grams of candy bar, then 30% of that is 30 grams (since 30/100 = 30%). Cut this in half and we end up with 30/2 = 15.

Another way to find the answer is to multiply 50 and 0.30 which is the decimal form of 30%. So we have 50*0.30 = 15 which is the same answer.

8 0
3 years ago
If y=1/2 when x=2, find y when x=3, given that y varies directly with x
Lelu [443]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=\frac{1}{2}\\
x=2
\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k
\\\\\\
\boxed{y=\cfrac{1}{4}x}
\\\\\\
\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3
4 0
3 years ago
HELPPPPP PLEASEEEEE
timama [110]

Answer:

19938383

Step-by-step explanation:

5 0
3 years ago
Lim x-0 (sin2xcsc3xsec2x)/x²cot²4x
sergij07 [2.7K]

By the definitions of cosecant, secant, and cotangent, we have

\dfrac{\sin2x\csc3x\sec2x}{x^2\cot^24x}=\dfrac{\sin2x\sin^24x}{x^2\sin3x\cos2x\cos^24x}

Then we rewrite the fraction as

\dfrac{\sin2x}{2x}\left(\dfrac{\sin4x}{4x}\right)^2\dfrac{3x}{\sin3x}\dfrac{32}{3\cos2x\cos^24x}

The reason for this is that we want to apply the well-known limit,

\displaystyle\lim_{x\to0}\frac{\sin ax}{ax}=\lim_{x\to0}\frac{ax}{\sin ax}=1

for a\neq0. So when we take the limit, we have

\displaystyle\lim_{x\to0}\cdots=\lim_{x\to0}\frac{\sin2x}{2x}\left(\lim_{x\to0}\frac{\sin4x}{4x}\right)^2\lim_{x\to0}\frac{3x}{\sin3x}\lim_{x\to0}\frac{32}3\cos2x\cos^24x}

=1\cdot1^2\cdot1\cdot\dfrac{32}3=\dfrac{32}3

8 0
3 years ago
Help as quick as possible
sp2606 [1]

Answer: A

Step-by-step explanation: i dont know i

thinks it a it could be wrong

7 0
2 years ago
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