For this case we have the following equation:
Where,
n: number of invitations:
c: cost in dollars
We note that the slope of the line for this case is:
The slope represents the cost of printing each of the invitations.
Therefore, it is false that the cost of printing each invitation is $ 5.50
Answer:
the following is not true:
A) each invitation costs $ 5.50 to print.
I hope this helped you! Good luck!
Answer:
0.017559
Step-by-step explanation:
Data provided:
Probability of Households Having cable TV, p₀ = 76% = 0.76
Therefore,
The probability that the Households not having cable TV = 1 - 0.76 = 0.24
Sample size, n = 225 households
sample proportions is less than 82% i.e p = 0.82
Now,
The standard error, SE = 
or
SE = 
or
SE = 0.02847
and,

or

or
Z = 2.107
therefore,
P(sample porportions < 0.82) = P(Z < 2.107)
now from the p value from the Z table
we get
P(sample porportions < 0.82) = 0.017559
Since Flying Falcon cost($8) is cheaper than Flying Bat($12), then the minimum possible cost each day would be the maximum possible Flying Falcon produced.
The maximum flying falcon produces is 60/day. Then, the amount of flying bat produced would be:
total= falcon + bat
70= 60+bat
bat= 70-60= 10
The minimum possible cost: falcon * falcon_cost + bat * bat_cost = 60*$8 + 10*$12 = $480+$120= $600
Answer:
H
Step-by-step explanation:
4x-4=-x-1 = 3/5 or .6