three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
the coordinates of point (x,y) on The terminal ray of angle theta, assuming that the values above we’re not simplified.
2 answers:
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
You might be interested in
I'll use a coordinate plane for this since it's easier (for me) :)
Red = park
Blue = his trail
Pink = distance from park = 3
Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)
Red = park
Blue = his trail
Pink = distance from park = 3
Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)
Answer:
<u>Approximately 16 tablets of medicine</u>
Step-by-step explanation:
Based on the information above , we can use a <u>Rule of Three</u> to first figure out how many mg the cat would need to ingest per day.
Now we see that the cat needs to take a daily dose of 22.5mg. Since the Tablets come at a strength of 10 mg per tablet then,
The cat would need to take 2.25 tablets per day. Since she needs to take the dose for the next 7 days then,
She would need to take<u> approximately 16 tablets of medicine</u> during the week .
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.