Answer:
Probability that exactly 5 of them favor the building of the health center is 0.0408.
Step-by-step explanation:
We are given that in a recent survey, 60% of the community favored building a health center in their neighborhood.
Also, 14 citizens are chosen.
The above situation can be represented through Binomial distribution;
![P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%20%5Cbinom%7Bn%7D%7Br%7Dp%5E%7Br%7D%20%281-p%29%5E%7Bn-r%7D%20%3B%20x%20%3D%200%2C1%2C2%2C3%2C.....)
where, n = number of trials (samples) taken = 14 citizens
r = number of success = exactly 5
p = probability of success which in our question is % of the community
favored building a health center in their neighborhood, i.e; 60%
<em>LET X = Number of citizens who favored building of the health center.</em>
So, it means X ~ ![Binom(n=14, p=0.60)](https://tex.z-dn.net/?f=Binom%28n%3D14%2C%20p%3D0.60%29)
Now, Probability that exactly 5 of them favor the building of the health center is given by = P(X = 5)
P(X = 5) = ![\binom{14}{5} \times 0.60^{5} \times (1-0.60)^{14-5}](https://tex.z-dn.net/?f=%5Cbinom%7B14%7D%7B5%7D%20%5Ctimes%200.60%5E%7B5%7D%20%5Ctimes%20%281-0.60%29%5E%7B14-5%7D)
= ![2002 \times 0.60^{5} \times 0.40^{9}](https://tex.z-dn.net/?f=2002%20%5Ctimes%200.60%5E%7B5%7D%20%5Ctimes%200.40%5E%7B9%7D)
= 0.0408
Therefore, Probability that exactly 5 of them favor the building of the health center is 0.0408.