Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
Answer:
r=28.27 cm aprox
Step-by-step explanation:
Well you know that the area of a circle is A= 
so
2511= so
=2511/
r=28.27 cm aprox
The answer is
8/4
7/5
4/3
7/10
Answer:
You put it over a one to represent seven whole numbers or just 7
We can get the Circumference of a circle with the diameter by using the formula:
Circumference = Diameter * pie
Where, pie = 22/7 = 3.14
Hope this helps!
