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3 years ago

7(2a−9)−(8a+2) Simplified please anyone?

Mathematics

1 answer:

Verizon [17]3 years ago

8 0

Answer:

6a+61

Step-by-step explanation:

7(2a-9)-(8a+2)

7x2a=14a

7x9=63

14a+63-(8a+2)

-1x8a=-8a

-1x2=-2

14a+63-8a-2

6a+61

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the length of a screwdriver is 19 centimeters. the handle is 5 centimeters long . what is the length of the top of the screw dri

svetoff [14.1K]

If the length of the entire screwdriver is 19cm, and the handle is 5cm, subtract the length of the handle from the total length to find the length of the top of the screwdriver.
19 - 5 = 14
The top of the screwdriver is 14cm long.

6 0

2 years ago

Write the equation of a line parallel to y= 2x + 2 that passes through the point (-1,-7). Show your work.

oksian1 [2.3K]

Answer:

$\large\boxed{y=2x-5}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

Parallel lines have the same slope. Therefore if given line is

$y=2x+2$

then the slope of our line is $m=2$ .

We have the equation:

$y=2x+b$

The line passes through (-1, -7). Put the coordinsted pf the point to the equation:

$-7=2(-1)+b$

$-7=-2+b$ add 2 to both sides

$-5=b\to b=-5$

Finally:

$y=2x-5$

6 0

3 years ago

URGENT WILL MARK BRAINLIEST Show your work and solve for x and y. 3x + y = 8 2x + 4y = 12

mars1129 [50]

3x+y=8--(1)

2x+4y=12

x+2y=6--(2)

(1)×1 and (2)×3

$\\ \rm\Rrightarrow 3x+y=8$

$\\ \rm\Rrightarrow 3x+6y=18$

Subtract both

$\\ \rm\Rrightarrow -5y=-10$

$\\ \rm\Rrightarrow y=\dfrac{-10}{-5}$

$\\ \rm\Rrightarrow y=2$

Put the value in eq(2)

$\\ \rm\Rrightarrow x+2(2)=6$

$\\ \rm\Rrightarrow x+4=6$

$\\ \rm\Rrightarrow x=6-4=2$

3 0

2 years ago

Read 2 more answers

I need the answer please asp

11Alexandr11 [23.1K]

Answer:

The answer is a isosceles right I think.

8 0

2 years ago

Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits,

Gennadij [26K]

Using proportions and the information given, it is found that:

The class width is of 14.375.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

Minimum value is 19.
Maximum value is of 134.
There are 8 classes.
The classes are all of equal width, thus the width is of:

$W = \frac{134 - 19}{8} = 14.375$

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0

3 years ago