Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:
(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:
Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:
Compute the probability of a person having a heart attack given that he or she has the disease:
The probability of a person having a heart attack given that he or she has the disease is 0.595.
Answer:
0.007%
Step-by-step explanation:
4000/28=0.007%
Answer:
The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Step-by-step explanation:
First, we need to separate the modulus from the rest of equation. So
3-l4-nl>1
-|4-n|>1-3
-|4-n|>-2
Multiplying everything by -1.
|4-n|<2
How to solve:
|x| < a means that -a<x<a
In this question:
|4-n|<2
-2<4-n<2
This means that:
4 - n > -2
-n > -6
Multiplying by -1
n < 6
And
4 - n < 2
-n < -2
Multiplying by 1
n > 2
Intersection:
Between n > 2 and n < 6 is 2 < n < 6
So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Answer:
minimum -45, maximum 32
Step-by-step explanation:
C=4x-3y
x≥0, y≥4, x+y≤15
Maximum value of C can be achieved at max x and min y
Minimum value of C can be achieved at min x and max y
So answer is minimum -45, maximum 32
Pls. see attachment. I created that table for easy monitoring and understanding.
Yellow cells are sums that are even.
Orange cell are sums that are multiples of 3.
Yellow cells w/ orange texts are sums that are both even and multiples of 3.
