The first relation gives two y-values for any given x-value (except x=6).
y² +x = 6 . . . . . is not a function
4m = 12x + 40
8x + 8x + 12x + 40 + 4m = 360
28x + 40 + 12x + 40 = 360
x = 7
m = 12(7) + 40 = 124
Hi there!
The question here is asking us to multiply two functions together - j(x) and k(x). First, we need to determine the expressions for j(x) and k(x). Since this is given, we can move straight onto multiplying the two functions together, which will give us our answer.
j(x) × k(x)
Substitute expressions -
(x⁴ - 81)(x + 3)
Simplify -
(x⁴ - 81)(x + 3)
x⁵ + 3x⁴ - 81x - 243
Therefore, the answer is x⁵ + 3x⁴ - 81x - 243. Hope this helped!
