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2 years ago

Which of the following is the quotient of the rational expressions shown

Mathematics

1 answer:

marusya05 [52]2 years ago

4 0

Answer:

A. $\frac{7x^2}{6x - 10}$

Step-by-step Explanation:

To get the quotient, which is the result of

What we get by dividing the above, we would turn the divisor upside down, while the division sign would change to multiplication. This rule applied is known as "multiplying by the reciprocal".

$\frac{7x^2}{2x + 6}$ ÷ $\frac{3x - 5}{x + 3}$

$\frac{7x^2}{2x + 6} * \frac{x + 3}{3x - 5}$ => multiplying by the reciprocal.

$\frac{7x^2}{2(x + 3)} * \frac{x + 3}{3x - 5}$

$\frac{7x^2}{2} * \frac{1}{3x - 5}$ => (x + 3) cancels (x + 3)

$\frac{7x^2(1)}{2(3x - 5)}$

$\frac{7x^2}{6x - 10}$

Quotient = $\frac{7x^2}{6x - 10}$

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Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai

ollegr [7]

Answer:

The probability that the aircraft is overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is overloaded ?

Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P( $\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma}$ )

= P( z > $\frac{168 - 182.7}{39.6}$ )

= P( z > -0.371)

= 1 - P ( z ≤ -0.371 )

= 1 - P( z > 0.371)

= 1 - 0.00010363

= 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

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so 2x+6 should be equal to 96

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Now we have to solve for x here and have to get x by itself on left hand side

So first get rid of +6 by doing its opposite -6 on both sides

2x + 6 -6 = 96 -6

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Now to get x by itself we have to get rid of 2, for that divide both sides by 2

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