
★ ∆ ABC is similar to ∆DEF
★ Area of triangle ABC = 64cm²
★ Area of triangle DEF = 121cm²
★ Side EF = 15.4 cm

★ Side BC

Since, ∆ ABC is similar to ∆DEF
[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

❍ <u>Putting the</u><u> values</u>, [Given by the question]
• Area of triangle ABC = 64cm²
• Area of triangle DEF = 121cm²
• Side EF = 15.4 cm

❍ <u>By solving we get,</u>






<u>Hence, BC = 11.2 cm.</u>

★ Figure in attachment.

you have to multiply by -3
so the answers are going to be one negative one positive
and the next 5th terms are 108,-324,972,-2916,8748
<span>A polygon has an angle sum of 360°, and each angle measures 90°. Let's find our what is the polygon.
=> 360 degrees polygon with 90 degree measure for each angles.
=> 360 degrees / 90 degrees = 4
Therefore the polygon is a square.</span>
Answer: the line is no longer linear
Step-by-step explanation: