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3 years ago

What is the shape of the cross-section formed when a cylinder intersects a plane as shown in the drawing?

Mathematics

1 answer:

Daniel [21]3 years ago

7 0

Answer:

B. rectangle

Step-by-step explanation:

it will be a rectangle with the dimension of diameter and height of the cylinder

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Using the SAS Congruence Theorem

marshall27 [118]

Sorry this got to you super late. At least others looking for the answer can find it.

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3 years ago

How many triangles in the diagram can be mapped to one another by similarity transformations?

Fynjy0 [20]

Answer:

the answer is 3

Step-by-step explanation:

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3 years ago

Read 2 more answers

What’s 1/3 • 5/4 and 1/5•2/3

Debora [2.8K]

Answer:

Step-by-step explanation:

1/2 + 2/3 + 5/4 = 29/

= 2 5/

≅ 2.4166667

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3 years ago

A parabola can be drawn given a focus of

Volgvan

Answer:

$y=-\frac{1}{4}(x-2)^{2}+9$

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at $(2,8)$ .

Directrix of the parabola is $y=10$ .

Let $(x,y)$ be any point on the parabola. Then, from the definition of a parabola,

Distance of $(x,y)$ from focus = Distance of $(x,y)$ from directrix.

Therefore,

$\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|$

Squaring both sides, we get

$(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9$

Hence, the equation of the parabola is $y=-\frac{1}{4}(x-2)^{2}+9$ .

4 0

3 years ago

What is the equation of the line that passes through (-3, -1) and has a slope of 3/5? Put your answer in slope-intercept form. y

zubka84 [21]

Answer:

Y=3/5x -4/5

Step-by-step explanation:

3/5 is the slope so you do 3/5x

-4/5 is negative because the line passes two negative coordinates

Hope this helps!

4 0

3 years ago