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anastassius [24]
3 years ago
14

Evaluate ,where e is the solid that lies between the cylinders x^2+y^2=1 and x^2+y^2=16, above the xy-plane, and below the plane

z=y+4
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
Assuming you're just computing the volume, i.e.

\displaystyle\iiint_E\mathrm dV

we should convert to cylindrical coordinates first, setting

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}

so that the volume is given by

\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\int_{\theta=0}^{\theta=2\pi}\int_{r=1}^{r=4}\int_{\zeta=0}^{\zeta=r\sin\theta+4}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta

which has a value of 60\pi.
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Martin is paid an hourly rate of d dollars per hour for the first 40 hours he works per week. He is paid one-and-a-half times hi
Nat2105 [25]

Answer:

40d + 10(1.5d) = 770 can be used to determine Martin's hourly pay.

Step-by-step explanation:

Given that:

Hourly rate = d

Earning to first 40 hours = 40d

Earning of more than 40 hours = 1.5d

Amount paid per week = $770

Hours worked = 50 hours

first 40 hours + 10 hours = total earned

40d + 10(1.5d) = 770

Hence,

40d + 10(1.5d) = 770 can be used to determine Martin's hourly pay.

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Step-by-step explanation:

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Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

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3 years ago
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