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Rainbow [258]
3 years ago
9

What did Mendel's cross pollination of pea plants prove

Biology
2 answers:
DaniilM [7]3 years ago
5 0
I'm pretty sure that the answer is D.
pashok25 [27]3 years ago
4 0

Answer: The correct answer is- D certain factors are dominant and other factors are recessive.

Mendel was interested in knowing the offspring that is produced from the cross pollination (that is from two different plants) as he wanted to study different traits of pea plant.

For doing so, he first removed the anthers of one plant (to prevent self pollination) and then transferred the pollens of one plant into the stigma of another plant.

When he allowed the cross pollination of purebred pea plant with other plant, he observed that some factors are dominant (such as tall height of pea plant, which masks the expression of recessive factors) and other are recessive (such as dwarf height of pea plant).

Thus, option D) is the right answer.

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The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A
ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

<em><u>Genotype       Observed frequency</u></em>

    A             →        18 individuals

    B             →        55 individuals

    C             →        27 individuals

Do these contradict the genetic model?  

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.  

Explanation:

<u>Available data</u>:

  • Crossed genotypes: two
  • Genotypes among the offspring; Three → A, B, and C
  • Expected phenotypic ratio → 1:2:1
  • Total number of individuals, N = 100
  • A = 18 individuals
  • B = 55 individuals
  • C = 27 individuals

So, let us first state the hypothesis:

  • H₀= the population is equilibrium for this locus → F(A) = 25%,  F(B) = 50%, F(C) = 25%  
  • H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 ---------------  25% -------------X = 25 individuals A

2 --------------  50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

<u>                                                   A                             B                           C</u>

  • Observed                         18                            55                         27
  • Expected                         25                           50                         25
  • (Obs-Exp)²/Exp                1.96                        0.5                        0.16

<u>(Obs-Exp)²/Exp</u>

A)  (18 - 25)²/25 = 49/25 = 1.96

B)  (55 - 50)² / 50 = 25/50 = 0.5

C)  (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp  

  • ∑ is the sum of the terms
  • O are the Observed individuals: 2 in chamber B, and 18 in chamber A.  
  • E are the Expected individuals: 10 in each chamber  

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05  

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99    

<em>These results suggest that there is </em><u><em>not enough evidence to reject</em></u><em> the null hypothesis. We can assume that </em><u><em>the locus under study in this population is in equilibrium H-W.  </em></u>

 

6 0
3 years ago
Which of the following statements about the smooth endoplasmic reticulum is/are correct?
Vlada [557]

Answer:

  • Liver cells are abundant in SER.  
  • The testes and ovaries are tissue types whose cells are abundant in SER.
  • Cholesterol is made in the SER.
  •  Phospholipids are synthesized from cytosolic water soluble precursor molecules.  

Explanation:

This is because liver cells contain enzymes that metabolize various lipid-soluble compounds.

This is because testes and ovaries produce steroid hormones (cholesterol is the precursor for their synthesis).

ER is the organelle at which all membrane lipids are synthesized.

Phospholipids are the main lipids that are the main structural components of the cell membrane. They are synthesized on the cytosolic side of the ER membrane, from water-soluble cytosolic precursors.

8 0
3 years ago
Describe the actual and relative sizes of a virus, a bacterium, and a plant or animal cell.
anzhelika [568]

Answer :

The animals are categorized into 2 groups - eukaryotes and prokaryotes. The microbes like bacteria are coming under prokaryotes. They are unicellular organisms and without a true nucleus.

Viruses are the connecting link between the living and non - living. They are smaller than bacteria. The microbes less than 100 micrometer can't be seen by the naked eye. They can only visible under a microscope.

Viruses like polio, flu virus sizes are 10nm. But some of the viruses are also less than 10nm. The size of bacteria is 1 micrometer. The viruses are 10 times smaller than the bacteria.

The eukaryotic organisms are more advanced and multicellular. Their cell size is larger than bacteria and viruses. The red blood cells under the light microscope are 8 micrometers. The typical animal cells like sperm are 60 micrometers and a skin cell is 30 micrometers. The plant cell for example pollen is 90 micrometers.

The eukaryotic cells sizes are more than prokaryotes like bacteria.

3 0
3 years ago
For the same insulation, order these regions from highest to lowest.
777dan777 [17]

Answer:

1. Lake Michigan

2. Grassy plains

3. An artic glacier

4. Sahara

Explanation:

8 0
2 years ago
Read 2 more answers
During Arjun's infection, S. pyogenes was growing in two very different environments-on the surface of his skin and in the deepe
DiKsa [7]

Answer:

Use Phosphotransferase system where glucose is not available.

Explanation:

Streptococcus pyogenes uses its phosphotransferase system for the uptake and metabolism of non-glucose carbohydrate sources in the environment where glucose is not available. Streptococcus pyogenes also uses malate which is a dicarboxylic organic acid that is present in large amount in both tissue and in the external environment. This malate is a non-glucose carbohydrate source used by Streptococcus pyogenes for the production of energy.

5 0
2 years ago
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