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PilotLPTM [1.2K]
4 years ago
13

Solve for (f+g)(5) if f(x)=6x+3 and g(x)=x-4 show you work please

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
7 0
There are two ways to do this.

The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34

OR

you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34

Either way, the final answer is 34

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3 years ago
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

\frac{d(u\cdot v)}{dx}=u'v+uv'

Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

3 0
3 years ago
The base of a prism is a regular hexagon with the perimeter of 78mm the height of the prism is 16mm what is the area of one of t
kifflom [539]
The perimeter is the sides of the hexagon. One of the hexagon edges is shared with a rectangular face. Solve for that edge. 78/6=13. The height is the length and edge is the width. Area is length(16) times width(13). 16•13=208. The answer is 208mm^2

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4 years ago
Find the value of x that will make A||B<br> 5x<br> 3x + 60<br> A<br> B<br> x= [?]<br> Enter
RSB [31]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Parallel lines.

To make them parallel ,just equate them.

5x = 3x + 60

===> 5x - 3x = 60

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4 0
3 years ago
Please help asap! i’m confused so please explain
maw [93]

Answer:

C

Step-by-step explanation:

Use SOHCAHTOA

to find h we will choose cos due to Adj is 8 and Hypotunse is h

cos 45 = 8/h

h= 8/cos 45

h = 11.3137

in surd form is 8root 2

USE A CALCULATOR TO CONFIRM FROM THE ANSWERS USING THE DECIMALS YOU GOT AS ANSWER

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