Answer:
36years
Step-by-step explanation:
Let charity present age be x
Charity daughter present age be y
Charity husband present age be z
If the sum of their ages ten years to come is 117, then;
10+x+10+y+10+z = 117
30+x+y+z = 117
x+y+z = 87 ... 1
If charity is four times as old as her daughter, then;
x = 4y
y = x/4 ... 2
If she is also six years younger than her husband, then;
x = z- 6
z = x+6 .. 3
Substitute 2 and 3 into 1;
x + x/4 + (x+6) = 87
Multiply through by 4
4x + x + 4(x+6) = 4(87)
5x+4x+24 = 348
9x = 348 - 24
9x = 324
x = 324/9
x = 36
hence Charity is 36years old today
Answer:
<em><u>(</u></em><em><u>C</u></em><em><u>)</u></em>
Step-by-step explanation:
<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☻</u></em><em><u>♨️</u></em><em><u>♨️</u></em><em><u>☻</u></em><em><u>☺️</u></em><em><u>❤</u></em>
Answer:
Step-by-step explanation:
33/3 = 11
36/3 =13
11 :13
(3x^2 - 5x +3) + (-2x -3x)
=3x^2-5x+3 + (6x^2)
=9x^2-5x+3
Answer:
12. B
13 A
18 B
19 B
Step-by-step explanation:
12. The solutions of the quadratic is the roots, so 0 = x^2 -7x -30 = (x-10)(x+3). For this to be satisfied, either x-10 = 0 -> x = 10 and x + 3 = 0 -> x = -3
13. Either x = 0 or x+8 = 0 -> x =-8 for this to be true
18. The GCF of 2, 6, and 20 is 2. No other number satisfies being a common factor.
19. The product of the solutions of the equation is the (constant/leading coefficient) in the quadratic, which is -8/1 = -8
I hope this helps! :)