Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 100
μ = mean = 125
σ = standard deviation = 18
z-score = (100 – 125) / 18
z-score = (-25) / 18
z-score = -1.39
Find the probability that corresponds to the z-score in the z-table. (see attached images)
-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968
-0.09 : -0.1 = x - 0.0968 : -0.016
x - 0.0968 = -0.09(-0.016)/-0.1
x = -0.0144 + 0.0968
x = 0.0824
x = 0.0824
Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
Learn more about probability here: brainly.com/question/26822684
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The appropriate choice is ...
... On Line 3, Brianna should have divided by 0.1 instead of subtracting 0.1.
_____
Had Brianna simplified her effort properly on line 4, she would have
... -0.1 +0.1x = -1.4
putting her essentially back where she started—with a 2-step equation.
Is it 6.5% per year?
Amount = Principle (1+rate*time)
<span> 22365 = 7000(1.065 * 3)
Interest = 22365 - 7000 = 15365</span>