Help me please!!!!!!!

What’s the coordinates for Y-3>2x+2 on a graph?

seropon [69]

Hmm the answer would be Yx3-10=43

5 0

2 years ago

What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.

V125BC [204]

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

$f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

$\dfrac{a}{b}$

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

$\dfrac{3}{x^2+9}$

The second fraction number given in the problem is,

$\dfrac{5}{x+3}$

Let the sum of these number is f(x). Thus,

$f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\$

Solve it further as,

$f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

Thus, the sum of the two fractional number is,

$f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

Learn more about the fraction number here:

brainly.com/question/78672

6 0

2 years ago

Choose the point-stope form of the equation below that represents the line that passes through the point (-1, 6) and has a slope

Keith_Richards [23]

Answer:

y-6 = -3(x+1)

Step-by-step explanation:

The point-slope form of a line is the following:

y-yo = m(x-xo), where 'm' is the slope and (xo, yo) is any point where the line passes through.

In this case, m=-3 and (xo, yo) = (-1, 6).

Therefore: y-yo = m(x-xo) = y-6 = -3(x+1)

In conclusion, the point-slope form of the equation that represents the line that passes through the point (-1, 6) and has a slope of -3 is:

y-6 = -3(x+1)

6 0

3 years ago

Read 2 more answers

Find sin(B), cos(B) and tan(B) for the right triangle ABC shown. Please show your work below.

tangare [24]

Hello!

These are the following formulas to calculate sine, cosine, and tangent.

sin = opposite / hypotenuse

cos = adjacent / hypotenuse

tan = opposite / adjacent

To find sin(B), we need to find the side opposite of angle B, and the hypotenuse.

The opposite of angle B is 12, and the hypotenuse is 13.

sin(B) = 12/13

sin^-1(12/13) = 67.3801... This can be rounded to 67.38 degrees. (Tenths place: 67.4 degrees)

To find cos(B), we need to find the side adjacent of angle B, and the hypotenuse.

The adjacent side of angle B is 5, and the hypotenuse is 13.

cos(B) = 5/13

cos^-1(5/13) = 67.3801... It can be rounded to 67.38 degrees. Rounded to the tenths place is 67.4 degrees.

To find cos(B), we need to find the side adjacent and opposite of angle B.

The adjacent side of angle B is 5, and the opposite is 12.

tan(B) = (12/5)

tan^-1(12/5) = 67.3801... This can be rounded to about 67.38 degrees. Rounded to the tenths place is 67.4 degrees.

Therefore, the value of sin(B) is 67.38 degrees, the value of cos(B) is 67.38 degrees, and finally the value of tan(B) is 67.38 degrees.

7 0

3 years ago

Read 2 more answers

Built in 1599, the Globe Theatre was home to William Shakespeare and his performing company, The Lord Chamberlain’s Men. It was

Sholpan [36]

You use the volume of a cylinder πr^2h

6 0

3 years ago