Question

In a little league baseball game, the 145 g ball enters the strike zone with a speed of 14.0m/s . the batter hits the ball, and it leaves his bat with a speed of 23.0m/s in exactly the opposite direction.what is the magnitude of the impulse delivered by the bat to the ball?if the bat is in contact with the ball for 1.0ms , what is the magnitude of the average force exerted by the bat on the ball?

Answer 1

Answer:

5365 N

Explanation:

v = Final velocity = 23 m/s

u = Initial velocity = -14 m/s (opposite direction)

m = Mass of ball = 145 g

t = Time taken = 1 ms

Impulse is given by

$J=m(v-u)$

Impulse is also given by

$J=Ft$

$Ft=m(v-u)\\\Rightarrow F=\dfrac{m(v-u)}{t}\\\Rightarrow F=\dfrac{0.145\times (23-(-14))}{1\times 10^{-3}}\\\Rightarrow F=5365\ N$

The magnitude of the average force exerted by the bat on the ball is 5365 N