It's called rifling, to stabilise the bullet.
Answer:
The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²
Explanation:
From the question, the given values are as follows:
Initial velocity, u = 90 m/s
final velocity, v = 0 m/s
distance, s = 110 m
acceleration, a = ?
Using the equation of motion, v² = u² + 2as
(90)² + 2 * 110 * a = 0
8100 + 220a = 0
220a = -8100
a = -8100/220
a = -36.81 m/s²
The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²
Answer:
N = 26.59 N
Explanation:
given,
mass = 0.38 kg
radius of the hoop = 1.10 m
speed = 5.35 m/s
force = ?
now,
we know that,
N = 26.59 N
Answer:
4.47 m/s.
Explanation:
distance traveled, d = 10 miles
time, t = 1 hour
Speed of the runner, v = d / t
Speed of the runner = 10 miles / 1
Speed of the runner = 10 mph
1 mph ----------------------- 0.44704 m/s
10 mph -----------------------?
= 4.47 m/s
Thus, in 2 hours the distance traveled will change but the speed it still 10 mph or 4.47 m/s.
Answer:
50
Explanation:
Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.
Brainliest, please :)
