How many star are thier in the universe

Physics

1 answer:

FrozenT [24]3 years ago

3 0

<h2>About 1 trillion billion stars (21 0's)</h2><h2 />

There is an average of 100 billion stars per galaxy. But you are looking for a universe, which is bigger than a galaxy.

According to UCSB Science Line, there are about 1 trillion billion stars in the observable universe. That's one 1 and twenty-one 0's.

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The acceleration due to gravity on the surface of Mars is about one-third the acceleration due to gravity on Earthâ€™s surface.

aksik [14]

Answer:

one-third of its weight on Earth's surface

Explanation:

Weight of an object is = W = m*g

Gravity on Earth = g₁ = 9.8 m/s

Gravity on Mars = g₂ = $\frac{1}{3}$ g₁

Weight of probe on earth = w₁ = m * g₁

Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )

As g₂ = g₁/3 --------- ( 2 )

Put equation (2) in equation (1)

Weight of probe on Mars = w₂ = m * g₁ /3

Weight of probe on Mars = $\frac{1}{3}$ m * g₁ = $\frac{1}{3}$ w₁

⇒Weight of probe on Mars = $\frac{1}{3}$ Weight of probe on earth

6 0

4 years ago

10. Hamilton How long does it take Lewis travelling at 156 m.p.h to cover 16 miles?

Anvisha [2.4K]

Answer: Hello!

Lewis is travelling at 165 mph, which means miles per hour, this says that he does 165 miles in one hour.

We want to know how much time takes to cover 16 miles.

this can be calculated as the quotient of the distance and the velocity; this is:

$t = \frac{16 mi}{165 mi/h} = 0.096 h$

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

0.096h*60mins/1h = 5.8 minutes.

then Lewis needs 5.8 minutes in order to cover 16 miles if his speed is 156 miles per hour.

6 0

3 years ago

Read 2 more answers

When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

Natali5045456 [20]

Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And $\theta$ be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration $gsin\theta$