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Wewaii [24]
3 years ago
10

How chips and number lines support the answer of 4+(-8)

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0
Chips and number lines support the answer because they can show the answer
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The number of students enrolled at a college is 17,000 and grows 6% each year.
Ad libitum [116K]

Answer:

1020 new students per year.

Step-by-step explanation:

5 0
3 years ago
For a family party, Tanisha made 2/5 of the dessert. If a total of 40 dessert were brought to the party, how many did Tanisha su
Pavel [41]
16 desserts 8+8+8+8+8= 40 so 2/5 of 40 is 16 
Hope this help Have a great day.
4 0
3 years ago
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What are the coordinates of the midpoint for segment AB if A is (14 , -2) and B is (7 , -8)
Alenkasestr [34]

Answer:

Step-by-step explanation:

(14 + 7)/2 = 21/2= 10.5

(-2 + (-8))/2= -10/2= -5

Midpoint(10.5, -5)

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3 years ago
2 thousands + 12 hundreds = write sum in standard form
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2000+1200=3200=thirty two hundreds
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3 years ago
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The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
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