First, you got to answer the question. The answer is 11/24, since 11 is a prime number that's your answer.
Answer:
g(3) = 11
g(-3) = 16
g(-1) =3
Step-by-step explanation:
For g(3)
g(x)= x² +2
g(3) = 3² + 2
g(3) = 9+2
g(3) = 11
For g(-3)
g(x) = -3x + 7
g(-3) = -3(-3) + 7
g(-3) = 9 + 7
g(-3) = 16
For g(-1)
g(x) = x² + 2
g(-1) = (-1)² +2
g(-1) = 1+2
g(-1) =3
Answer:εδΑΒΓΒΕ
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Step-by-step explanation:
73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Cross-multiply:
7 * 3 = 5 * x
Divide each side by 5 :
X = 7 * 3 / 5 = 4.2
