Question

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers.

Answer 1

X+y+z=92

y=3x

z=2x-10
subsitute
x+3x+2x-10=92
6x-10=92
add 10 to both sdies
6x=102
divide by 6
x=17
subsitute

y=3x
y=3(17)
y=51

z=2x-10
z=2(17)-10
z=34-10
z=24



x=17
y=51
z=24

the numbers are 17,51,24

Answer 2

Always let x equal the number you don't know anything about in this case it's the first number. x= first 3x= second 2x-10= third add and equal to 92 6x-10=92 6x=102 x=17. first substitute 17 for x in the original expressions 51= second 24=third