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Lena [83]
3 years ago
13

Pls help will mark brainliest if right !

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

some

some

some

some

no

Step-by-step explanation:

SSSSS [86.1K]3 years ago
5 0

Answer:

1) no triangles

2)some triangles

3)no triangles

4)no triangles

5)all triangles

Step-by-step explanation:

i think that is right not sure tho

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The radius of a circular puddle is growing at a rate of 25 cm/sec.
tatiyna

Answer:

Step-by-step explanation:

a)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,r =50

rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854

area growing 7854 cm2/s

b)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,A =64

pi r^2 =64

=>r =8/√pi

rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98

area growing 708.98 cm2/s

8 0
3 years ago
What is the area of this figure?<br><br> Enter your answer in the box.
earnstyle [38]
To find the area you do base times height. Base is the number across,and height is the number that is up and down.So in this case you will multiply 9 and 5 and 9 and 7 and get 45 and 72.Then you will add 45 and 72 together and get 117. So the area is 117. Answer 117. Hope this helps :D.
5 0
3 years ago
Read 2 more answers
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
The ratio of boys to girls in Janice’s classroom is 3:5, and there are a total of 32 students in the class. Using complete sente
AleksAgata [21]
divide and then multiple the numbers!
3 0
3 years ago
√−100 = ___ +_____i<br> ...
Natalija [7]

Answer:

Step-by-step explanation:

Rewrite this as

\sqrt{(-1)(100)}

Knowing that i-squared = -1:

\sqrt{(i^2)(100)}

Both i-squared and 100 are perfect squares, so this simplifies to

±10i

7 0
3 years ago
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