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Scilla [17]
2 years ago
11

Substitution to determine if 19 was a solution to the equation

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
7 0

Answer:

Step-by-step explanation:

if your question is
"Choose the student who correctly used substitution to determine if 19 was a solution to the equation. 6 + m = 24. 6 + 19 = 24. 24 = 24. 19 is a solution. 6 + m = 24. 6 + 19 = 24. 25 not-equals 24. 19 is not a solution. 6 + m = 24. 6 + 24 = 24. 30 not-equals 24. 19 is not a solution. 6 + m = 24. 6 + 19 = 24. 25 = 24. 19 is a solution."

then juan is correct

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Write an absolute value equation that has the solutions x=−6 and x=10
Dimas [21]
x^{2} +6x-60=0
3 0
3 years ago
Find the interior angles of a regular polygon which has 6, 10 and 20 sides​
andrew-mc [135]

Answer:

(6)=120°

(10)=72°

(20)=36°

Step-by-step explanation:

(n-2)×180°

(6-2)×180°=720°

6÷720°=120°

10÷720°=72°

20÷720°=36°

4 0
3 years ago
PLEASE HELP
max2010maxim [7]

Hello!


So, this is quite the complex question, and here are the following steps:


What is the quotient of \frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}?

\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (rationalize the denominator)

\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

5 0
3 years ago
What is the LCM of 8 and 10
iragen [17]
40


8x5=40
10x4=40

Hope this helps
3 0
2 years ago
Which equation is the Pythagorean theorem
lisov135 [29]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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